Tokyo Institute of Technology (M1) Rearch Interest: Visualization"> 剑指 Offer 05. 替换空格 Posted on 2023-05-24 Edited on 2022-02-11 In LeetCode , Easy , Half-done 转载自Leet Code《剑指Offer》 题目描述 请实现一个函数,把字符串 s 中的每个空格替换成"%20"。 示例: 输入:s = "We are happy." 输出:"We%20are%20happy." 提示: 0 <= s 的长度 <= 10000 我的代码 {.line-numbers}123456class SolutionOffer05 { public String replaceSpace(String s) { String str = s.replaceAll(" ", "%20"); return str; }}